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Software Engineering
Accenture Technical PrimermediumSoftware Engineering04 Looping Statements

Consider the output: 0, 2, 4, 6, 8 ,10 ,12, 16 Which of the below given pseudo code snippet gives the above output?

Answer options

A
BEGIN DECLARE number, count, even SET count <-- 16, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 Number <--5 num2ber+2 1 48 END WHILE PRINT even END
B
BEGIN DECLARE number, count, even SET count <-- 8, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 number <-- number + 1 END WHILE PRINT even END
C
BEGIN DECLARE number, count, even SET count <-- 8, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 Number <-- number+ 2 END WHILE END
D
BEGIN DECLARE number, count, even SET count <-- 8, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 1 Number <-- number+ 1 END WHILE PRINT even END

Correct answer: BEGIN DECLARE number, count, even SET count <-- 16, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 Number <--5 num2ber+2 1 48 END WHILE PRINT even END

Explanation

Quick AnswerThe correct answer is BEGIN DECLARE number, count, even SET count <-- 16, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 Number <--5 num2ber+2 1 48 END WHILE PRINT even END because it directly addresses the core logic of Software Engineering.

Correct answer: BEGIN DECLARE number, count, even SET count <-- 16, number <-- 0, even <-- 0 WHILE number<count PRINT even SET even <-- even + 2 Number <--5 num2ber+2 1 48 END WHILE PRINT even END.

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